When 10 m l of 0.2 M solution of an acid is added to 250 m l of a buffer solution with p H = 6.34 , the p H of the solution becomes 6.32 . The buffer capacity of the solution is:

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Explanation: The expression for the buffer capacity is as follows:Buffer capacity = Number of moles of acid or base added per litre Change in p H 10 m l of 0.2 M acid is added to 250 m l of a buffer solution. Number of moles of acid added = 0.2 × 10 1000 Therefore, the number of moles of acid added per litre, = 0.2 × 10 1000 × 1000 250 = 0.008 Change in p H = 6.34 − 6.32 = 0.02 Substituting values in the above expression, we get,Buffer capacity = 0.008 0.02 = 0.4 Therefore, the buffer capacity is 0.4 .Hence, the correct option is (D).

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When $10 m l$ of $0.2 M$ solution of an acid is added to $250 m l$ of a buffer solution with $p H = 6.34$ , the $p H$ of the solution becomes $6.32$ . The buffer capacity of the solution is:

The Correct Option is D

Solution and Explanation

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When 10ml of 0.2M solution of an acid is added to 250ml of a buffer solution with pH=6.34, the pH of the solution becomes 6.32. The buffer capacity of the solution is:

The Correct Option is D

Solution and Explanation

Top Questions on Structure of atom

Questions Asked in MHT CET exam

When $10 m l$ of $0.2 M$ solution of an acid is added to $250 m l$ of a buffer solution with $p H = 6.34$ , the $p H$ of the solution becomes $6.32$ . The buffer capacity of the solution is: