Question:
When 1-chlorobutane is treated with aqueous KOH it gives P. However, when treated with alcoholic KOH it gives Q. Identify P and Q respectively.
When 1-chlorobutane is treated with aqueous KOH it gives P. However, when treated with alcoholic KOH it gives Q. Identify P and Q respectively.
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Use aqueous KOH for substitution, alcoholic KOH for elimination reactions.
Updated On: May 18, 2025
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The Correct Option is C
Solution and Explanation
Aqueous KOH leads to nucleophilic substitution (SN2) — alcohol is formed.
Alcoholic KOH leads to β-elimination — alkene is formed.
So, P = CH$_3$CH$_2$CH$_2$CH$_2$OH, Q = CH$_3$CH=CHCH$_3$ (2-butene)
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