print(16 * 5 / 4 * 2 / 5 - 8)
-3.33
0.0
The given expression evaluates step by step according to the precedence of arithmetic operators (division and multiplication from left to right, followed by subtraction):
\[ 16 \times 5 = 80, \quad 80 \div 4 = 20, \quad 20 \times 2 = 40, \quad 40 \div 5 = 8, \quad 8 - 8 = 0.0. \]
Therefore, the output of the statement is \( 0.0 \).
The correct IUPAC name of \([ \text{Pt}(\text{NH}_3)_2\text{Cl}_2 ]^{2+} \) is: