Question

What is the value of the ionization energy of hydrogen in joules? (Given that the ionization energy of hydrogen is \( 13.6 \, \text{eV} \))

• A. \( 2.18 \times 10^{-18} \, \text{J} \)
• B. \( 1.6 \times 10^{-18} \, \text{J} \)
• C. \( 3.2 \times 10^{-19} \, \text{J} \)
• D. \( 1.0 \times 10^{-19} \, \text{J} \)

Hint:

Remember: To convert from eV to joules, multiply by \( 1.6 \times 10^{-19} \, \text{J/eV} \). This is useful when dealing with energy calculations in atomic physics.

Answer 1

The Correct Option is A

Step 1: Convert ionization energy from eV to joules 1 electronvolt (eV) is equal to \( 1.6 \times 10^{-19} \, \text{J} \). Therefore, the ionization energy of hydrogen in joules can be calculated by multiplying the energy in eV by the conversion factor: \[ E_{\text{ionization}} = 13.6 \, \text{eV} \times 1.6 \times 10^{-19} \, \text{J/eV} \] Step 2: Calculate the ionization energy \[ E_{\text{ionization}} = 13.6 \times 1.6 \times 10^{-19} = 21.76 \times 10^{-19} = 2.18 \times 10^{-18} \, \text{J} \] Answer: Therefore, the ionization energy of hydrogen is \( 2.18 \times 10^{-18} \, \text{J} \). So, the correct answer is option (1).