Question

What is the time period of a simple pendulum of length \( L \) and acceleration due to gravity \( g \)?

• A. \( 2\pi \sqrt{\frac{L}{g}} \)
• B. \( 2\pi \sqrt{\frac{g}{L}} \)
• C. \( \frac{2\pi}{\sqrt{L}} \)
• D. \( \frac{2\pi}{g} \)

Hint:

The time period of a simple pendulum depends on its length and the acceleration due to gravity but is independent of the mass of the pendulum.

Answer 1

The Correct Option is A

The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}}, \] 

where \( L \) is the length of the pendulum and \( g \) is the acceleration due to gravity. 

Therefore, the correct answer is option (1).