Question:
What is the relative rate of \( \text{S}_\text{N}1 \) reaction for \( (\text{CH}_3)_2\text{CH–Br} \)?
What is the relative rate of \( \text{S}_\text{N}1 \) reaction for \( (\text{CH}_3)_2\text{CH–Br} \)?
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Relative rates of \( \text{S}_\text{N}1 \) reactions depend on carbocation stability.
Updated On: Jan 26, 2026
- \(10^6\)
- Less than \(10^{-4}\)
- \(0.02\)
- \(1.0\)
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The Correct Option is D
Solution and Explanation
Step 1: Nature of the substrate.
\((\text{CH}_3)_2\text{CH–Br}\) is a secondary alkyl halide.
Step 2: Reference standard.
In relative rate studies of \( \text{S}_\text{N}1 \) reactions, secondary alkyl halides are taken as the standard with rate equal to 1.
Step 3: Conclusion.
Therefore, the relative rate of the \( \text{S}_\text{N}1 \) reaction is \(1.0\).
\((\text{CH}_3)_2\text{CH–Br}\) is a secondary alkyl halide.
Step 2: Reference standard.
In relative rate studies of \( \text{S}_\text{N}1 \) reactions, secondary alkyl halides are taken as the standard with rate equal to 1.
Step 3: Conclusion.
Therefore, the relative rate of the \( \text{S}_\text{N}1 \) reaction is \(1.0\).
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