Question

What is the relative error percentage of an observation taken by an ultrasonic sensor which predicts the distance of an object to be (2)12 cm but the actual value is 2 cm?

• A. 12%
• B. 10%
• C. 6%
• D. 1%

Hint:

Error Calculation. Absolute Error = |Measured - Actual|. Relative Error = Absolute Error / Actual Value. Percentage Error = Relative Error \(\times\) 100%.

Answer 1

The Correct Option is C

Measured Value = (2)12 cm Actual (True) Value = (2)00 cm Absolute Error = Measured Value - Actual Value Absolute Error = (2)12 cm - (2)00 cm = 0
12 cm Relative Error = \(\frac{\text{Absolute Error}}{\text{Actual Value}}\) Relative Error = \(\frac{0
12 \, \text{cm}}{(2)00 \, \text{cm}} = 0
06\) Relative Error Percentage = Relative Error \(\times\) 100% Relative Error Percentage = 0
06 \(\times\) 100% = 6%