Question:

What is the probability of not getting an odd number in a throw of a die once?

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The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
Updated On: Oct 27, 2025
  • 0
  • \( \frac{1}{2} \)
  • \( \frac{1}{3} \)
  • 1
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The Correct Option is B

Solution and Explanation

In a single throw of a die, the numbers on the die are: 1, 2, 3, 4, 5, 6. The odd numbers are 1, 3, 5, so there are 3 odd numbers. The numbers that are not odd (i.e., the even numbers) are 2, 4, 6, so there are 3 even numbers. The probability of not getting an odd number is the ratio of even numbers to the total number of possible outcomes: \[ P(\text{Not odd}) = \frac{3}{6} = \frac{1}{2}. \] Thus, the correct answer is \( \frac{1}{2} \).
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