Question:

What is the oxidation state of sulfur in \( \text{H}_2\text{SO}_4 \)?

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In compounds like \( \text{H}_2\text{SO}_4 \), balance the oxidation states of all atoms to find the oxidation state of the central atom.
Updated On: Apr 15, 2025
  • +4
  • +6
  • -2
  • 0
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The Correct Option is B

Solution and Explanation

In \( \text{H}_2\text{SO}_4 \), hydrogen has an oxidation state of +1, oxygen has an oxidation state of -2. Let the oxidation state of sulfur be \( x \). The sum of oxidation states in a neutral compound must be zero. Therefore: \[ 2 \times (+1) + x + 4 \times (-2) = 0 \] \[ 2 + x - 8 = 0 \] \[ x = +6 \] Thus, the oxidation state of sulfur in \( \text{H}_2\text{SO}_4 \) is +6.
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