In \( \text{Cr}_2\text{O}_3 \), oxygen has an oxidation state of -2 (since oxygen typically has an oxidation state of -2).
Let the oxidation state of chromium be \( x \). For the compound to be neutral, the sum of the oxidation states must be zero.
The total oxidation state of the oxygen atoms is \( 3 \times (-2) = -6 \).
Therefore, the total oxidation state of the two chromium atoms must be +6 to balance the -6 from the oxygen atoms.
Since there are 2 chromium atoms, the oxidation state of each chromium atom is:
\[
\frac{+6}{2} = +3
\]
Thus, the oxidation state of chromium in \( \text{Cr}_2\text{O}_3 \) is +3.