Question:

What is the nature of the roots of the quadratic equation \( \frac{4}{3}x^2 - 2x + \frac{3}{4} = 0 \)?

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For real and equal roots, the discriminant \( \Delta = 0 \).
Updated On: Oct 27, 2025
  • Real and unequal
  • Real and equal
  • Not real
  • None of these
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The Correct Option is A

Solution and Explanation

We need to determine the nature of the roots of the quadratic equation \( \frac{4}{3}x^2 - 2x + \frac{3}{4} = 0 \). The nature of the roots depends on the discriminant \( \Delta \), given by: \[ \Delta = b^2 - 4ac. \] For the equation \( \frac{4}{3}x^2 - 2x + \frac{3}{4} = 0 \), we have \( a = \frac{4}{3} \), \( b = -2 \), and \( c = \frac{3}{4} \). The discriminant is: \[ \Delta = (-2)^2 - 4 \times \frac{4}{3} \times \frac{3}{4} = 4 - 4 = 0. \] Since the discriminant is zero, the roots are real and equal. Thus, the roots are \( \boxed{\text{Real and equal}} \).
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