The Reimer-Tiemann reaction is used to introduce a formyl group (-CHO) at the ortho position to the hydroxyl group on a benzene ring. When phenol undergoes this reaction, the major product formed is o-hydroxybenzaldehyde, also known as salicylaldehyde, which has both a hydroxyl group and an aldehyde group on the aromatic ring.
- Option (A) is incorrect because the reaction does not lead to the formation of benzaldehyde.
- Option (C) is incorrect because p-Hydroxybenzoic acid is not formed in this reaction.
- Option (D) is incorrect as o-Nitrophenol is unrelated to this reaction.
Therefore, the correct answer is option (B).