>
Exams
>
Mathematics
>
Polynomials
>
what is the degree of the polynomial 7u 6 3 2 u 4
Question:
What is the degree of the polynomial
\(7u^6 - \frac{3}{2}u^4 + 6u^2 - 8\)
?
TS POLYCET - 2021
TS POLYCET
Updated On:
Dec 6, 2024
7
\(\frac{-3}{2}\)
6
-8
Hide Solution
Verified By Collegedunia
The Correct Option is
C
Solution and Explanation
The correct option is (C): 6
Download Solution in PDF
Was this answer helpful?
0
1
Top Questions on Polynomials
Find the zeroes of the polynomial $f(t) = t^2 + 4\sqrt{3}t - 15$ and verify the relationship between the zeroes and the coefficients of the polynomial.
CBSE Class X - 2024
Mathematics
Polynomials
View Solution
The graph of a polynomial intersects the y-axis at one point and the x-axis at two points. The number of zeroes of this polynomial are :
CBSE Class X - 2024
Mathematics
Polynomials
View Solution
Assertion (A):
Zeroes of a polynomial
\(p(x) = x^2 − 2x − 3\)
are -1 and 3.
Reason (R):
The graph of polynomial
\(p(x) = x^2 − 2x − 3\)
intersects the x-axis at (-1, 0) and (3, 0).
CBSE Class X - 2024
Mathematics
Polynomials
View Solution
If one of the zeroes of the quadratic polynomial \((\alpha - 1)x^2 + \alpha x + 1\) is \(-3\), then the value of \(\alpha\) is:
CBSE Class X - 2024
Mathematics
Polynomials
View Solution
For what value of \(k\), the product of zeroes of the polynomial \(kx^2 - 4x - 7\) is 2?
CBSE Class X - 2024
Mathematics
Polynomials
View Solution
View More Questions
Questions Asked in TS POLYCET exam
The value of
\(\tan 26^\circ. \tan 64^\circ\)
is
TS POLYCET - 2023
Trigonometry
View Solution
When white light is incident on a glass prism, the least deviated colour is
TS POLYCET - 2023
Wave Optics
View Solution
If 5x+py+8=0 and 10x+15y+12=0 has no solution, then p =
TS POLYCET - 2023
Quadratic Equations
View Solution
If
\(\sec \theta = \frac{2}{\sqrt{3}}\)
,then
\(cosθ=\)
TS POLYCET - 2023
Trigonometry
View Solution
In the figure, if AP and AQ are the two tangents to a circle with centre 'O' so that
\(∠OQP=15°\)
, then
\(∠QAP=\)
TS POLYCET - 2023
Tangent to a Circle
View Solution
View More Questions