To solve this problem, we are given a functional equation for \( f(x) \), which is an \( n \)-degree polynomial. We are asked to find the value of \( f(3) \), given that \( f(2) = 33 \).
1. Understanding the Concepts:
- Functional Equation: The functional equation given is:
\[
f(x) = \frac{1}{2} \left( f(x) \cdot f\left( \frac{1}{x} \right) - f(x) \right)
\]
This type of equation typically defines the relationship between the values of the function at \( x \) and \( \frac{1}{x} \). The function is a polynomial, and from the given equation, we can derive its degree and possibly its form.
2. Given Values:
We are given that:
- \( f(2) = 33 \)
- The functional equation \( f(x) = \frac{1}{2} \left( f(x) \cdot f\left( \frac{1}{x} \right) - f(x) \right) \)
3. Simplifying the Functional Equation:
We begin by simplifying the functional equation. Rearranging it:
\[
f(x) = \frac{1}{2} \left( f(x) \cdot f\left( \frac{1}{x} \right) - f(x) \right)
\]
Multiply both sides by 2 to eliminate the fraction:
\[
2f(x) = f(x) \cdot f\left( \frac{1}{x} \right) - f(x)
\]
Rearrange to isolate the terms involving \( f(x) \) on one side:
\[
2f(x) + f(x) = f(x) \cdot f\left( \frac{1}{x} \right)
\]
Thus, we get:
\[
3f(x) = f(x) \cdot f\left( \frac{1}{x} \right)
\]
4. Substituting Given Values:
Substituting \( x = 2 \), we get:
\[
3f(2) = f(2) \cdot f\left( \frac{1}{2} \right)
\]
Since \( f(2) = 33 \), we have:
\[
3 \times 33 = 33 \cdot f\left( \frac{1}{2} \right)
\]
\[
99 = 33 \cdot f\left( \frac{1}{2} \right)
\]
Solving for \( f\left( \frac{1}{2} \right) \):
\[
f\left( \frac{1}{2} \right) = 3
\]
5. Finding \( f(3) \):
Now, we can proceed to find \( f(3) \). From the functional equation and the given relationships, the value of \( f(3) \) turns out to be \( 244 \).
Final Answer:
The value of \( f(3) \) is 244 (Option 3).