Question:
What is the decreasing order of strength of the bases?
$OH^{-},NH_2^-,H-C \equiv C^- \, and \, CH_3-CH_2^- $
What is the decreasing order of strength of the bases?
$OH^{-},NH_2^-,H-C \equiv C^- \, and \, CH_3-CH_2^- $
Updated On: Jul 7, 2022
- $CH_3-CH_2^- > NH_2^- > H-C \equiv C^- > OH^- $
- $H-C \equiv C^-> CH_3-CH_2^- > NH_2^- > OH^- $
- $OH^- > NH_2^- > H-C \equiv C^- > CH_3-CH_2^- $
- $NH^-_2 > H -C \equiv C^- > OH^- > CH_3-CH_2^- $
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The Correct Option is A
Solution and Explanation
$CH_3CH_2^- > NH_2^- > H-C \equiv C^- > HO^- $
It is because the order of acid-strength of their conjugate acid is
$CH_3CH_3 < NH_3 < H-C \equiv C-H < H_2O: $ Acid strength.
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