Question

What is the decreasing order of strength of the bases? $OH^{-},NH_2^-,H-C \equiv C^- \, and \, CH_3-CH_2^- $

• A. $CH_3-CH_2^- > NH_2^- > H-C \equiv C^- > OH^- $
• B. $H-C \equiv C^-> CH_3-CH_2^- > NH_2^- > OH^- $
• C. $OH^- > NH_2^- > H-C \equiv C^- > CH_3-CH_2^- $
• D. $NH^-_2 > H -C \equiv C^- > OH^- > CH_3-CH_2^- $

Answer 1

The Correct Option is A

$CH_3CH_2^- > NH_2^- > H-C \equiv C^- > HO^- $ It is because the order of acid-strength of their conjugate acid is $CH_3CH_3 < NH_3 < H-C \equiv C-H < H_2O: $ Acid strength.