Question:

What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, $g = 10\,m/s^{-2}$) of an air-craft flying at a speed of $400\,m/s$ through a circular arc of radius $0.6\,km$ ?

Updated On: Jun 14, 2022
  • $26.7$
  • $16.9$
  • $13.5$
  • $30.2$
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The Correct Option is A

Solution and Explanation

Here, $v = 400 \,m \,s^{-1}$,
$r = 0.6 \,km = 0.6 \times 10^3\,m$,
$g = 10\, m s^{-2}$
Centripetal acceleration,
$a_{c}=\frac{v^{2}}{r}$
$\frac{\left(400\,m\,s^{-1}\right)^{2}}{0.6\times10^{3}\,m}$
$=26.7\times10^{3}\,ms^{-2}$
In the units of $g(= 10 \,m s^{-2})$, the centripetal acceleration is $26.7$.
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration