Question

What are X and Y respectively in the following reaction sequence?  

• A. $\text{NH}_2\text{NH}_2, \quad \text{C}_6\text{H}_5\text{SO}_2\text{Cl} / \text{Pyridine}$
• B. $\text{NH}_2\text{NH}_2, \quad (\text{CH}_3\text{CO})_2\text{O}$
• C. $\text{NH}_2\text{OH}, \quad \text{C}_6\text{H}_5\text{SO}_2\text{Cl} / \text{Pyridine}$
• D. $\text{NH}_2\text{OH}, \quad (\text{CH}_3\text{CO})_2\text{O}$

Hint:

For oxime formation, always use hydroxylamine ($\text{NH}_2\text{OH}$). For conversion to nitriles, use reagents like acetic anhydride or acidic catalysts.

Answer 1

The Correct Option is D

Understanding the reaction mechanism.
- The first step involves the formation of an oxime (X), which is typically done by reacting an aldehyde with hydroxylamine ($\text{NH}_2\text{OH}$).
- The second step converts the oxime to a nitrile (Y), which is done using acetic anhydride ($(\text{CH}_3\text{CO})_2\text{O}$) in a Beckmann rearrangement.