Question

What are X and Y respectively in the following reaction sequence?  

• A. \( \text{NH}_2\text{NH}_2, \quad \text{C}_6\text{H}_5\text{SO}_2\text{Cl} / \text{Pyridine} \)
• B. \( \text{NH}_2\text{NH}_2, \quad (\text{CH}_3\text{CO})_2\text{O} \)
• C. \( \text{NH}_2\text{OH}, \quad \text{C}_6\text{H}_5\text{SO}_2\text{Cl} / \text{Pyridine} \)
• D. \( \text{NH}_2\text{OH}, \quad (\text{CH}_3\text{CO})_2\text{O} \)

Hint:

For oxime formation, always use hydroxylamine (\(\text{NH}_2\text{OH}\)). For conversion to nitriles, use reagents like acetic anhydride or acidic catalysts.

Answer 1

The Correct Option is D

Understanding the reaction mechanism.
- The first step involves the formation of an oxime (X), which is typically done by reacting an aldehyde with hydroxylamine (\(\text{NH}_2\text{OH}\)).
- The second step converts the oxime to a nitrile (Y), which is done using acetic anhydride (\((\text{CH}_3\text{CO})_2\text{O}\)) in a Beckmann rearrangement.