What are the reagents X and Y respectively used in the following reaction sequence to convert a nitrile to a methyl group?
The conversion of a nitrile to a methyl group involves significant reduction, typically requiring strong reducing agents and conditions that facilitate both reduction and hydrolysis.
Step 2: Analyze the selected option.SnCl\(_2\) in the presence of HCl (reagent X) is used initially to reduce the nitrile group partially, likely to an imine.
H\(_3\)O\(^+\) (part of reagent Y) then hydrolyzes the imine to an amine.
The final step involves the use of Zn-Hg amalgam in concentrated HCl (additional part of reagent Y), which is a classic Clemmensen reduction, reducing the amine further to a methyl group. This sequence of reactions is particularly effective for fully reducing nitrile to a primary alkyl group without over-reduction or unwanted side reactions.
To solve this problem, we need to identify the reagents X and Y that are used in the given reaction sequence:
1. Understanding the Reaction:
The reaction involves a compound with a nitrile group (R-C≡N) reacting with X and Y to form an alkyl group (R-CH3). This type of reaction typically involves a reduction of the nitrile group (C≡N) to an amine or an aldehyde, and subsequent reduction or substitution to yield a methyl group.
2. Evaluating the Options:
Let's look at the reaction steps and identify the reagents:
3. Conclusion:
Based on the typical reaction sequence for the reduction of nitriles to aldehydes, Option B (SnCl2, HCl, and Zn-Hg) is the most appropriate set of reagents for this reaction.
Final Answer:
The correct answer is Option B: (i) SnCl2, HCl (ii) H3O+; (ii) Zn-Hg | Conc. HCl.
List-I | List-II | ||
(A) | NH3 | (I) | Trigonal Pyramidal |
(B) | BrF5 | (II) | Square Planar |
(C) | XeF4 | (III) | Octahedral |
(D) | SF6 | (IV) | Square Pyramidal |
(1) \( x_1 = y_1 \)
(2) \( \frac{x_1 + x_2}{2} = \frac{y_1 + y_2}{2} \)
(3) \( x_2 = y_2 \)
(4) \( (x_1 - x_2)^2 = (y_1 - y_2)^2 \)