- Assume 100 g solution:
Glucose = 20 g, Water = 80 g.
- Moles of glucose: \[ \frac{20}{180} = 0.111 \]
- Moles of water: \[ \frac{80}{18} = 4.44 \] - Total moles = \(0.111 + 4.44 = 4.551\) Mole fractions: \[ x_{{glucose}} = \frac{0.111}{4.551} = 0.0244 \] \[ x_{{water}} = \frac{4.44}{4.551} = 0.9756 \]
If the probability distribution of a random variable X is as follows, then the mean of X is
X = xi | -1 | 0 | 1 | 2 |
P(X = xi) | k3 | 2k3 + k | 4k - 10k2 | 4k - 1 |
The mean deviation about the mean for the following data is
Class Interval | 0--2 | 2--4 | 4--6 | 6--8 | 8--10 |
Frequency | 1 | 3 | 4 | 1 | 2 |
$\left( 1 + \sqrt{5} + i \sqrt{10 - 2\sqrt{5}} \right)^5$