From Statement I: the product of the three ages is 21.
Possible triplets: \( (1,3,7), (1,1,21), (3,3,3), (7,1,3) \), etc. But age order is not fixed.
Statement II: The sum is not divisible by 3.
Let’s examine possible sums:
- \(1 + 3 + 7 = 11\) → not divisible by 3
- \(3 + 3 + 3 = 9\) → divisible by 3
- \(1 + 1 + 21 = 23\) → not divisible by 3
Even combining both statements, multiple valid combinations still exist.
Hence, we cannot uniquely determine the three brothers' ages.