Question

What is the cost of 3 mocktails and one cocktail in the society club?
Statement A: The cost of three cocktails is twice the cost of six mocktails.
Statement B: The cost of two mocktails is equal to the cost of one cocktail which is Rupees 500.

• A. If Statement A is alone sufficient to answer
• B. If Statement B is alone sufficient to answer
• C. If both the statements are needed to answer
• D. Cannot answer from both statements using together

Hint:

When dealing with problems involving costs and quantities, express the relationship between the variables algebraically, and use the given information to find specific values.

Answer 1

The Correct Option is B

Let the cost of one mocktail be \( x \) and the cost of one cocktail be \( y \). Step 1: Analyze Statement A.
Statement A gives the relationship between the cost of three cocktails and six mocktails: \[ 3y = 2 \times 6x \quad \Rightarrow \quad 3y = 12x \quad \Rightarrow \quad y = 4x \] This equation provides a relationship between the cost of a cocktail and a mocktail, but we still need more information to find the individual costs of the mocktail and cocktail. Therefore, Statement A alone is not sufficient. Step 2: Analyze Statement B.
Statement B tells us that the cost of two mocktails is equal to the cost of one cocktail, and the cost of one cocktail is Rs. 500: \[ 2x = y = 500 \quad \Rightarrow \quad x = 250 \] So, the cost of one mocktail is Rs. 250, and the cost of one cocktail is Rs. 500. Step 3: Calculate the total cost.
The total cost of 3 mocktails and one cocktail is: \[ 3 \times 250 + 500 = 750 + 500 = 1250 \] Step 4: Conclusion.
Therefore, the cost of 3 mocktails and one cocktail is Rs. 1250, which can be directly answered using Statement B alone. Hence, the correct answer is option (2).