Question:

Water rises in a capillary tube of radius \( r \) upto a height \( h \). The mass of water in a capillary is \( m \). The mass of water that will rise in a capillary of radius \( \frac{r}{4} \) will be

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The capillary rise is proportional to \( \frac{1}{r} \) and the mass of water is proportional to \( r^2 \).
Updated On: Jan 27, 2026
  • \( \frac{m}{4} \)
  • \( m \)
  • \( 4m \)
  • \( m \)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding capillary rise.
The height to which water rises in a capillary tube is inversely proportional to the radius of the tube. That is, the capillary rise for a tube with radius \( r/4 \) is four times greater than that for a tube with radius \( r \).
Step 2: Conclusion.
The mass of water that rises is proportional to the cross-sectional area of the tube, which depends on the square of the radius. Therefore, the mass of water in the tube with radius \( r/4 \) will be \( \frac{m}{4} \).
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