Water falls from 100 metre height. What will be temperature rise per kg of water due to fall?
\(g = 10 \, \text{m/s}^2\), specific heat of water = 4200 Joule/kg°C
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The temperature rise due to work done by gravity is calculated using the equation \(mgh = mc\Delta T\).
The work done by gravity is converted into heat energy, which increases the temperature. The work done is:
\[
W = mgh
\]
The heat energy is related to the temperature rise by:
\[
Q = mc\Delta T
\]
Equating the two:
\[
mgh = mc\Delta T
\]
Solving for \(\Delta T\), we find that the temperature rise is 2.238°C.