Question

A sphere of 150 kg is kept on frictionless surface. A bullet of 0.15 kg mass with velocity 200 m/sec strikes the sphere and stops. After collision the velocity of sphere will be

• A. 0.2 m/sec
• B. 2.0 m/sec
• C. 0.3 m/sec
• D. 0.5 m/sec

Hint:

When two objects collide, use the conservation of momentum to find the final velocity of the objects.

Answer 1

The Correct Option is A

By applying the law of conservation of momentum: \[ m_1v_1 + m_2v_2 = (m_1 + m_2)v_f \] where \(m_1 = 0.15 \, \text{kg}\), \(v_1 = 200 \, \text{m/s}\), \(m_2 = 150 \, \text{kg}\), and \(v_2 = 0\). Solving for \(v_f\), the final velocity of the sphere is 0.2 m/s.