Question:
Values of \(\epsilon^0\) Reduction are given below as:-
\(Sn^{2+} |Sn = -0.14V, Zn^{2+} |Zn = -0.76V, Cr^{3+} |Cr = -0.74V\\Mg^{2+} | Mg = -2.36V\)
The ion which will get deposited at cathode in an electrochemical cell would be
Values of \(\epsilon^0\) Reduction are given below as:-
\(Sn^{2+} |Sn = -0.14V, Zn^{2+} |Zn = -0.76V, Cr^{3+} |Cr = -0.74V\\Mg^{2+} | Mg = -2.36V\)
The ion which will get deposited at cathode in an electrochemical cell would be
\(Sn^{2+} |Sn = -0.14V, Zn^{2+} |Zn = -0.76V, Cr^{3+} |Cr = -0.74V\\Mg^{2+} | Mg = -2.36V\)
The ion which will get deposited at cathode in an electrochemical cell would be
Updated On: Apr 26, 2024
- \(Sn^{2+}\)
- \(Zn^{2+}\)
- \(Cr^{3+}\)
- \(Mg^{2+}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): Sn2+
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