Question:
Value of \(\int_c\frac{2z+1}{z^2+z}dz\), where C is\(|z|=\frac{1}{2}\), is:
Value of \(\int_c\frac{2z+1}{z^2+z}dz\), where C is\(|z|=\frac{1}{2}\), is:
Updated On: Apr 28, 2025
- -2πi
- 2πi
- πi
- 0
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The Correct Option is B
Solution and Explanation
The correct option is(B): 2πi
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