(i) Fe3+(aq) + e- \(\rightarrow\) Fe2+(aq) ] × 2; \(E^0\)= +0.77 V
2I-(aq) \(\rightarrow\) I2(s) + 2e- ; \(E^0\)= -0.54 V
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2 Fe3+(aq) + 2I-(aq) \(\rightarrow\) 2Fe2+(aq) + I2(s) ; \(E^0\) = +0.23 V
Since\(E^0\) for the overall reaction is positive, the reaction between Fe3+(aq and I-(aq) is feasible.
(ii) Ag+(aq) + e- → Ag(s) ] × 2 ; \(E^0\)= +0.80 V
Cu(s) → Cu2+(aq) + 2e- ; \(E^0\)= -0.34 V
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2Ag+(aq)+ Cu(s) → 2Ag(s) + Cu2+(aq) ; \(E^0\) = +0.46 V
Since \(E^0\) for the overall reaction is positive, the reaction between Ag+(aq) and Cu(s) is feasible
(iii) Fe3+(aq)+e- → Fe2+(aq) ] × 2 ; \(E^0\) = +0.77 V
2Br-(aq) → Br2(l) + 2e- ; \(E^0\)= -1.09 V
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Since \(E^0\) for the overall reaction is negative, the reaction between Fe3+(aq) and Br-(aq)is not feasible
Ag(s) \(\rightarrow\) Ag+(aq) + e- ; \(E^0\) = -0.80 V
Fe3+(aq) + e- \(\rightarrow\) Fe2+(aq) ; \(E^0\) = +0.77 V
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Ag(s) + Fe3+(aq) \(\rightarrow\) Ag+(aq) + Fe2+(aq) ; \(E^0\) = -0.03 V
Since \(E^0\) for the overall reaction is negative, the reaction between Ag(s) and Fe3+(aq) is not feasible.
(v) Br2(aq) +2e- → 2Br-(aq) ;\(E^0\) = +1.09 V
Fe2+(aq) → Fe3+(aq) + e- ] × 2 ; \(E^0\) = - 0.77 V
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Br2(aq) + 2Fe2+(aq) → 2Br-(aq) +2Fe3+(aq) ;\(E^0\) = +0.32 V
Since\(E^0\) for the overall reaction is positive, the reaction between Br2(aq) and Fe2+(aq) is feasible.
The molar conductance of an infinitely dilute solution of ammonium chloride was found to be 185 S cm$^{-1}$ mol$^{-1}$ and the ionic conductance of hydroxyl and chloride ions are 170 and 70 S cm$^{-1}$ mol$^{-1}$, respectively. If molar conductance of 0.02 M solution of ammonium hydroxide is 85.5 S cm$^{-1}$ mol$^{-1}$, its degree of dissociation is given by x $\times$ 10$^{-1}$. The value of x is ______. (Nearest integer)
Consider the following half cell reaction $ \text{Cr}_2\text{O}_7^{2-} (\text{aq}) + 6\text{e}^- + 14\text{H}^+ (\text{aq}) \longrightarrow 2\text{Cr}^{3+} (\text{aq}) + 7\text{H}_2\text{O}(1) $
The reaction was conducted with the ratio of $\frac{[\text{Cr}^{3+}]^2}{[\text{Cr}_2\text{O}_7^{2-}]} = 10^{-6}$
The pH value at which the EMF of the half cell will become zero is ____ (nearest integer value)
[Given : standard half cell reduction potential $\text{E}^\circ_{\text{Cr}_2\text{O}_7^{2-}, \text{H}^+/\text{Cr}^{3+}} = 1.33\text{V}, \quad \frac{2.303\text{RT}}{\text{F}} = 0.059\text{V}$
| Concentration of KCl solution (mol/L) | Conductivity at 298.15 K (S cm-1) | Molar Conductivity at 298.15 K (S cm2 mol-1) |
|---|---|---|
| 1.000 | 0.1113 | 111.3 |
| 0.100 | 0.0129 | 129.0 |
| 0.010 | 0.00141 | 141.0 |
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
An electrochemical cell is a device that is used to create electrical energy through the chemical reactions which are involved in it. The electrical energy supplied to electrochemical cells is used to smooth the chemical reactions. In the electrochemical cell, the involved devices have the ability to convert the chemical energy to electrical energy or vice-versa.