Question:

Two uniformly charged spherical conductors, A and B of radii 5 mm and 10 mm are separated by a distance of 2 cm. If the spheres are connected by a conducting wire, then in equilibrium condition, the ratio of the magnitude of the electric fields at surface of the spheres A and B will be

Updated On: Mar 19, 2025
  • 1:2
  • 2:1
  • 1:1
  • 1:4
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Spheres after connecting with a conducting wire :

\(σ_1R_1 = σ_2R_2\)

Then, \(E = \frac{σ }{ ∈_0}\)

Hence, the ratio of the magnitude of the electric fields at surface of the spheres A and B will be : 

\(⇒ \frac{E_1}{E_2}\)

\(\frac{σ_1}{σ_2}\)

\(\frac{R_2}{R_1}\)

\(\frac{2}{1}\)

Hence, the correct option is (B): \(2:1\)

Was this answer helpful?
0
0

Concepts Used:

Electric Field

Electric Field is the electric force experienced by a unit charge. 

The electric force is calculated using the coulomb's law, whose formula is:

\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)

While substituting q2 as 1, electric field becomes:

 \(E=k\dfrac{|q_{1}|}{r^{2}}\)

SI unit of Electric Field is V/m (Volt per meter).