Two thin lenses have a combined power of +9D. When they are separated by a distance of 20 cm, then their equivalent power becomes +27/5 D. Their individual power (in dioptre) is
Let P1 and P2 are the power of lenses.
Peq = P1 + P2
Given, Peq = 9
P1 + P2 = 9 ………………(1)
Power of lenses when distance is separated by d = 0.2 m ,
P'eq = P1 + P2 − dP1P2
Given, P'eq =\(\frac {27}{5}\)
\(\frac {27}{5}\) = 9 − 0.2 P1P2
on solving P1P2=18
P2 = \(\frac {18}{P_1}\)
From eq (1)
P1 + \(\frac {18}{P_1}\) = 9 …………(2)
P12 + 18 = 9 P1
P12 − 9P1+18=0
on solving P1 = 6 D
Now from eq (1)
6 + P2 = 9
P2 = 9 - 6
P2 = 3 D
Therefore the correct option is (A) 3,6
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?
Lenses that are made by combining two spherical transparent surfaces are called spherical lenses. In general, there are two kinds of spherical lenses. Lenses that are made by joining two spherical surfaces that bulge outward are convex lenses, whereas lenses that are made by joining two spherical surfaces that curve inward are concave lenses.