\[ P(A) = \frac{1}{10}, \quad P(B|A) = \frac{3}{5}, \quad P(A|B^c) = \frac{1}{5} \] Using the law of total probability: \[ P(B) = P(B|A) P(A) + P(B|A^c) P(A^c) \] Since, \[ P(A^c) = 1 - P(A) = 1 - \frac{1}{10} = \frac{9}{10} \] And given: \[ P(B|A^c) = 1 - P(A|B^c) = 1 - \frac{1}{5} = \frac{4}{5} \] Substituting the values: \[ P(B) = \frac{3}{5} \times \frac{1}{10} + \frac{4}{5} \times \frac{9}{10} \] \[ = \frac{3}{50} + \frac{36}{50} = \frac{39}{50} = 0.78 \]
Based upon the results of regular medical check-ups in a hospital, it was found that out of 1000 people, 700 were very healthy, 200 maintained average health and 100 had a poor health record.
Let \( A_1 \): People with good health,
\( A_2 \): People with average health,
and \( A_3 \): People with poor health.
During a pandemic, the data expressed that the chances of people contracting the disease from category \( A_1, A_2 \) and \( A_3 \) are 25%, 35% and 50%, respectively.
Based upon the above information, answer the following questions:
(i) A person was tested randomly. What is the probability that he/she has contracted the disease?}
(ii) Given that the person has not contracted the disease, what is the probability that the person is from category \( A_2 \)?