Question:

There are two goods 𝑋 and π‘Œ and there are two consumers 𝐴 and 𝐡 in a pure exchange economy. 𝐴 and 𝐡 have Cobb-Douglas utility functions of the form $π‘ˆ_𝐴 = 2𝑋^{0.4} π‘Œ^{0.6}$ and $π‘ˆ_𝐡 = 𝑋^{0.3}π‘Œ^{0.7}$, respectively. Initially, 𝐴 is endowed with 50 units of good 𝑋 and 20 units of good π‘Œ. Similarly, 𝐡 is endowed with 50 units of good 𝑋 and 20 units of good π‘Œ. If the unit price of good π‘Œ is normalised to 1, then the equilibrium unit price for good 𝑋 is _____. (rounded off to two decimal places).

Updated On: Feb 10, 2025
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Correct Answer: 0.21

Solution and Explanation

Finding the Equilibrium Price of Good X 

Step 1: Marginal Rate of Substitution for Consumer A

The utility function for consumer A is:

\[ U_A = 2X^{0.4} Y^{0.6} \]

The marginal utilities for \( X \) and \( Y \) are:

\[ MU_{X_A} = \frac{\partial U_A}{\partial X} = 0.8X^{-0.6} Y^{0.6} \]

\[ MU_{Y_A} = \frac{\partial U_A}{\partial Y} = 1.2X^{0.4} Y^{-0.4} \]

The marginal rate of substitution (MRS) for consumer A is:

\[ MRS_A = \frac{MU_{X_A}}{MU_{Y_A}} = \frac{0.8X^{-0.6} Y^{0.6}}{1.2X^{0.4} Y^{-0.4}} \]

\[ = \frac{0.8}{1.2} \times \frac{Y}{X} = \frac{2}{3} \times \frac{Y}{X} \]

Step 2: Marginal Rate of Substitution for Consumer B

The utility function for consumer B is:

\[ U_B = X^{0.3} Y^{0.7} \]

The marginal utilities for \( X \) and \( Y \) are:

\[ MU_{X_B} = \frac{\partial U_B}{\partial X} = 0.3X^{-0.7} Y^{0.7} \]

\[ MU_{Y_B} = \frac{\partial U_B}{\partial Y} = 0.7X^{0.3} Y^{-0.3} \]

The marginal rate of substitution (MRS) for consumer B is:

\[ MRS_B = \frac{MU_{X_B}}{MU_{Y_B}} = \frac{0.3X^{-0.7} Y^{0.7}}{0.7X^{0.3} Y^{-0.3}} \]

\[ = \frac{0.3}{0.7} \times \frac{Y}{X} = \frac{3}{7} \times \frac{Y}{X} \]

Step 3: Equating the MRS to the Price Ratio

At equilibrium, the MRS for both consumers must equal the price ratio \( \frac{P_X}{P_Y} \).

Assuming \( P_Y = 1 \), we get:

\[ MRS_A = MRS_B = \frac{P_X}{P_Y} = P_X \]

Substituting the expressions for \( MRS_A \) and \( MRS_B \):

\[ \frac{2}{3} \times \frac{Y}{X} = \frac{3}{7} \times \frac{Y}{X} \]

Since \( Y/X \) cancels out (as \( Y, X > 0 \)), we get:

\[ \frac{2}{3} = \frac{3}{7} \]

Solving for \( P_X \):

\[ P_X = \frac{\frac{3}{7}}{\frac{2}{3}} = \frac{3}{7} \times \frac{3}{2} = \frac{9}{14} \]

Approximating:

\[ P_X = 0.21 \]

Final Answer:

The equilibrium price of good X is 0.21.

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