Two solid cylinders P and Q of same mass and same radius start rolling down a fixed inclined plane from the same height at the same time. Cylinder P has most of its mass concentrated near its surface, while Q has most of its mass concentrated near the axis. Which statement(s) is(are) correct?
Both cylinders P and Q reach the ground at the same time
Cylinder P has larger linear acceleration than cylinder Q
Both cylinders reach the ground with same translational kinetic energy
Cylinder Q reaches the ground with larger angular speed
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The Correct Option isD
Solution and Explanation
$Ip > Iq$ In case of pure rolling, $a=\frac{g sin ?}{1+I/mR^2}$ $a_Q > a_P$ as its moment of inertia is less. Therefore, Q reaches first with more linear speed and more translational kinetic energy. Further, $?=\frac{V}{R}$ or $??v$ $\therefore ?_Q > ?_P$ as $v_P > v_Q$
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