When light is reflected from a surface, the reflected ray is completely polarized at the Brewster's angle. The Brewster's angle \(\theta_B\) is given by the relation: \[ \tan(\theta_B) = n \] where \(n\) is the refractive index of the material. For ray B to be completely polarized, the angle of incidence must be the Brewster's angle. For ray B, the angle of incidence is \(60^\circ\). Therefore, \[ \tan(60^\circ) = n \] We know that \(\tan(60^\circ) = \sqrt{3}\). Hence, \[ n = \sqrt{3} \approx 1.732 \]
So, the correct option is (E) : \(1.732\)
For a ray to be completely polarized after reflection, it must satisfy Brewster’s law, which states:
\(\mu = \tan \theta_B\)
where:
\(\mu\) = refractive index of glass
\(\theta_B\) = Brewster’s angle
In the given question, ray B is completely polarized at an angle of incidence of 60°. So,
\(\mu = \tan 60^\circ = \sqrt{3} = 1.732\)
Correct Option: 1.732
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?