Question:

Two particles P and Q located at the points \( P(t, t^3 - 16t - 3) \), \( Q(t+1, t^3 - 6t - 6) \) are moving in a plane. The minimum distance between the points in their motion is:

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Use the distance formula between moving points and minimize using calculus or algebraic simplification.
Updated On: May 19, 2025
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The Correct Option is A

Solution and Explanation

Let \( P = (t, t^3 - 16t - 3) \), \( Q = (t+1, t^3 - 6t - 6) \). The distance between P and Q is \[ D(t) = \sqrt{(1)^2 + [(t^3 - 6t - 6) - (t^3 - 16t - 3)]^2} = \sqrt{1 + (10t + 3)^2} \] Minimize \( D(t) \Rightarrow \) minimize \( (10t + 3)^2 \Rightarrow t = -\frac{3}{10} \) gives minimum value \[ D = \sqrt{1 + 0} = 1 \]
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