Question:

Two metal wires of same length, same area of cross-section have conductivities of their material \( \sigma_1 \) and \( \sigma_2 \). If they are connected in series, the effective conductivity is:

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For conductors in series, use the formula \( \frac{2 \sigma_1 \sigma_2}{\sigma_1 + \sigma_2} \) to find the effective conductivity.
Updated On: May 15, 2025
  • \( \frac{\sigma_1 \sigma_2}{\sigma_1 + \sigma_2} \)
  • \( \frac{2 \sigma_1 \sigma_2}{\sigma_1 + \sigma_2} \)
  • \( \frac{\sigma_1}{\sigma_2} \)
  • \( \frac{2 \sigma_1}{\sigma_2} \)
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The Correct Option is B

Solution and Explanation

When two conductors are connected in series, the effective conductivity is given by \( \frac{2 \sigma_1 \sigma_2}{\sigma_1 + \sigma_2} \), which is similar to the formula for resistances in parallel. Thus, the correct answer is option (2).
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