Question

Two liquids A and B are in the ratio 5 : 1 in container 1 and 1 : 3 in container 2. In what ratio should the contents of the two containers be mixed so as to obtain a mixture of A and B in the ratio 1 : 1?

• A. 2 : 3
• B. 4 : 3
• C. 3 : 2
• D. 3 : 4

Hint:

Use alligation or weighted average method for mixture ratio problems.

Answer 1

The Correct Option is C

Container 1: A fraction = 5/6, Container 2: A fraction = 1/4. Let mixing ratio be $m:n$. Final A fraction = $(5m/6 + n/4)/(m+n) = 1/2$. Solve: $10m/12 + 3n/12 = (m+n)/2 \Rightarrow 10m+3n = 6m+6n \Rightarrow 4m = 3n \Rightarrow m:n = 3:2$.