Question:
Two insulated circular loop A and B radius ‘a’ carrying a current of ‘I’ in the anti clockwise direction as shown in figure. The magnitude of the magnetic induction at the centre will be :
Two insulated circular loop A and B radius ‘a’ carrying a current of ‘I’ in the anti clockwise direction as shown in figure. The magnitude of the magnetic induction at the centre will be :
Updated On: Nov 11, 2024
- \( \frac{\sqrt{2} \mu_0 I}{a} \)
- \( \frac{\mu_0 I}{2a} \)
- \( \frac{\mu_0 I}{\sqrt{2} a} \)
- \( \frac{2 \mu_0 I}{a} \)
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The Correct Option is C
Solution and Explanation
Calculate the magnetic field at the center due to one loop:
\[ B = \frac{\mu_0 I}{2a} \]
Since there are two loops in perpendicular planes, the resultant magnetic field is:
\[ B_{\text{net}} = \sqrt{B^2 + B^2} = \frac{\mu_0 I}{\sqrt{2}a} \]
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