When two identical sphere come in contact with each other, the total charge on them is equally distribute.
\(\frac{kQ^2}{d^2}\)=F
F=\(\frac{k9Q^2}{16×\frac{d^2}{4}}−\frac{k3Q^2}{8×\frac{d^2}{4}}\)
=\(\frac{9kQ^2}{4d^2}−\frac{3kQ^2}{2d^2}\)
=\(\frac{kQ^2}{d^2}[\frac{9}{4}−\frac{3}{2}]\)
=\(\frac{6}{8}F\)
=\(\frac{3}{4}F\)
So, the correct option is (B): \(\frac{3}{4}F\)
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to:
A spherical mirror is a mirror which has been cut out of a spherical surface.
There are two kinds of spherical mirrors:
Concave mirrors are also called converging mirrors, because in these types of mirrors, light rays converge at a point after impact and reflect back from the reflective surface of the mirror.
The convex mirror has a reflective surface that is curved outward. Regardless of the distance between the subject and the mirrors, these mirrors are "always" virtual, upright and reduced.