Question:

Two glass plates are separated by water. If surface tension of water is $75$ dyne/cm and area of each plate wetted by water is $8\, cm ^{2}$ and the distance between the plates is $0.12 \,mm$, then the force applied to separate the two plates is

Updated On: Jun 23, 2023
  • $ 10^2$ dyne
  • $ 10^4$ dyne
  • $10^5$ dyne
  • $10^6$ dyne
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The Correct Option is C

Solution and Explanation

The shape of water layer between the two plates is shown in the figure.


Thickness $d$ of the film $=0.12\, mm$
$=0.012\, cm$
Radius $R$ of the cylindrical face $=\frac{d}{2}$
Pressure difference across the surface
$=\frac{T}{R}=\frac{2 T}{d}$
Area of each plate wetted by water $=A$
Force $F$ required to separate the two plates is given by
$F=$ pressure difference $ \times $ area
$=\frac{2 T}{d} A$
Putting the given values, we get
$F=\frac{2 \times 75 \times 8}{0.012}=10^{5} $ dyne
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Concepts Used:

Surface Tension

The amount of energy required to increase the liquid's surface area by one unit area is known as surface tension. In other words, it is a property of the liquid surface to resist force.

Surface tension is defined as,

The ratio of the surface force F to the length L along which the force acts.

Mathematically, the surface tension formula can be expressed as follows:

T=F/L

Where,

  • F is the force per unit length
  • L is the length in which force act
  • T is the surface tension of the liquid

Read More: Detergents and Surface Tension

Factors affecting surface tension:

  • Impurities: The surface tension decreases with the addition of impurities.
  • Surfactants: Adding surfactants in liquids lowers the tension of water making it interrupt aside or get susceptible.
  • Temperature: The surface tension of a liquid reduces as the temperature rises.

The Unit of Surface Tension:

The SI unit of Surface Tension is Newton per Meter or N/m.