Given:
Two coins are tossed simultaneously.
We are to find the probability of getting at least one head.
Step 1: List all possible outcomes
When two coins are tossed, the possible outcomes are:
- HH (Head, Head)
- HT (Head, Tail)
- TH (Tail, Head)
- TT (Tail, Tail)
So, total number of outcomes = 4
Step 2: Count favorable outcomes
Outcomes with at least one head are:
- HH
- HT
- TH
Number of favorable outcomes = 3
Step 3: Calculate Probability
\[
\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{4}
\]
Final Answer:
The probability of getting at least one head is \(\frac{3}{4}\).