Question:

Two coins are tossed simultaneously. The probability of getting at least one head is

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List all outcomes to count favorable events in probability problems.
Updated On: Jun 2, 2025
  • $\dfrac{1}{4}$
  • $\dfrac{1}{2}$
  • $\dfrac{3}{4}$
  • 1
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The Correct Option is C

Solution and Explanation

Given:
Two coins are tossed simultaneously.
We are to find the probability of getting at least one head.

Step 1: List all possible outcomes
When two coins are tossed, the possible outcomes are:
- HH (Head, Head)
- HT (Head, Tail)
- TH (Tail, Head)
- TT (Tail, Tail)
So, total number of outcomes = 4

Step 2: Count favorable outcomes
Outcomes with at least one head are:
- HH
- HT
- TH
Number of favorable outcomes = 3

Step 3: Calculate Probability
\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{4} \]

Final Answer:
The probability of getting at least one head is \(\frac{3}{4}\).
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