Question:

Two balls, having linear momenta $ \rho_1 = p \widehat{i} $ and $\rho_2 = - p \widehat{i}, $ undergo a collision in free space. There is no external force acting on the balls. Let $ \rho_2 ' \, and \, \rho_2 ' $. be their final momenta. The following option figure (s) is (are) not allowed for any non-zero value of $ \rho, a_1, a_2, b_1, b_2, c_1 \, and c_2$.

Updated On: Jun 14, 2022
  • $ \rho_1' = a_1 \widehat{ i } + b_1 \widehat{ j} + c_1 \widehat{k}, \rho_2 = a_2 \widehat{ i } + b_2 \widehat{ j} $
  • $ \rho_1 ' = c_1 \widehat{ k} , \rho_2 = c_2 \widehat{ k} $
  • $ \rho_1' = a_1 \widehat{ a_1 } \widehat{ i} + b_1 \widehat{ j } + c_1 \widehat{k} , \rho_2 = a_2 \widehat{ i } + b_2 \widehat{ j} - c_1 \widehat{ k} $
  • $ \rho_1 ' = a_1 \widehat{i} + b_1 \widehat{j} + c_1 \widehat{k}, \rho_2 = a_2 \widehat{i} + b_1 \widehat{j}$
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The Correct Option is D

Solution and Explanation

Initial momentum of the system $ \rho_1 + \rho_2 = 0 $
$\therefore$ Final momentum $ \rho_1 ' + \rho_2 ' $ should also be zero
Option (b) is allowed because if we put $ c_1 = - c_2 \ne 0, $
$ \rho_1 ' + \rho_2 ' $ W'H t>e zero. Similary, we can check other options.
$\therefore$ Correct options are (a) and (d).
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.