Treatment of D-glucose with aqueous NaOH results in a mixture of monosaccharides, which are
The Correct Option is C
Approach Solution - 1
D-glucose with aq.NaOH results in a mixture of mannose, glucose and fructose in equilibrium via enediol intermediate (Tautomerization).
So the correct option is (C)
Approach Solution -2
The reaction of D-glucose with aqueous NaOH results in a mixture of monosaccharides. This is an example of an aldose, where glucose (a reducing sugar) undergoes an aldol reaction in the presence of NaOH, which leads to the formation of aldose and ketose forms.
Step 1: Reaction of D-glucose with NaOH
When D-glucose is treated with aqueous NaOH, it undergoes an aldol condensation reaction. During this process, D-glucose is converted into a mixture of monosaccharides, which are both aldose and ketose forms. In the presence of NaOH, the aldose group of glucose undergoes a rearrangement, forming two possible isomers. The aldose isomer remains the same, but the ketose isomer forms a structural rearrangement where the carbonyl group is shifted. The aldose form maintains the original structure, whereas the ketose form undergoes the necessary changes in the carbonyl group and hydroxyl positions.
Step 2: Identifying the Correct Monosaccharides
The treatment of D-glucose with NaOH results in the following monosaccharides:
- One molecule retains the aldose structure and is still a glucose molecule,
- The other molecule undergoes the transformation to form a fructose structure (a ketose),
These two forms are:
The aldose form, which is still glucose,
The ketose form, which is fructose.
Step 3: Identifying the Correct Option
The correct option is C, where the mixture of monosaccharides formed are glucose (the aldose form) and fructose (the ketose form).
The correct option is C.
Top Questions on Glucose
- Which of the following shows -R effect?
Assume a living cell with 0.9% (\(w/w\)) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water. (Consider the data up to first decimal place only) The cell will:
Identify correct conversion during acidic hydrolysis from the following:
(A) Starch gives galactose.
(B) Cane sugar gives equal amount of glucose and fructose.
(C) Milk sugar gives glucose and galactose.
(D) Amylopectin gives glucose and fructose.
(E) Amylose gives only glucose.
Choose the correct answer from the options given below:- Given are 4 statements related to the chemical properties of Glucose. Identify the two incorrect statements from the following.
- Describe the development of placenta during pregnancy in a human female.
Questions Asked in JEE Advanced exam
- Let $ x_0 $ be the real number such that $ e^{x_0} + x_0 = 0 $. For a given real number $ \alpha $, define $$ g(x) = \frac{3xe^x + 3x - \alpha e^x - \alpha x}{3(e^x + 1)} $$ for all real numbers $ x $. Then which one of the following statements is TRUE?
- JEE Advanced - 2025
- Fundamental Theorem of Calculus
- At 25$^\circ$C, the concentration of H$^+$ ions in $ 1.00 \times 10^{-3} \, \text{M} $ aqueous solution of a weak monobasic acid having acid dissociation constant $ K_a = 4.00 \times 10^{-11} $ is $ X \times 10^{-7} \, \text{M} $. The value of $ X $ is ____. {Use: Ionic product of water $ K_w = 1.00 \times 10^{-14} $ at 25$^\circ$C
- JEE Advanced - 2025
- Ionic Equilibrium
- Consider the vectors $$ \vec{x} = \hat{i} + 2\hat{j} + 3\hat{k},\quad \vec{y} = 2\hat{i} + 3\hat{j} + \hat{k},\quad \vec{z} = 3\hat{i} + \hat{j} + 2\hat{k}. $$ For two distinct positive real numbers $ \alpha $ and $ \beta $, define $$ \vec{X} = \alpha \vec{x} + \beta \vec{y} - \vec{z},\quad \vec{Y} = \alpha \vec{y} + \beta \vec{z} - \vec{x},\quad \vec{Z} = \alpha \vec{z} + \beta \vec{x} - \vec{y}. $$ If the vectors $ \vec{X}, \vec{Y}, \vec{Z} $ lie in a plane, then the value of $ \alpha + \beta - 3 $ is ________.
Two identical concave mirrors each of focal length $ f $ are facing each other as shown. A glass slab of thickness $ t $ and refractive index $ n_0 $ is placed equidistant from both mirrors on the principal axis. A monochromatic point source $ S $ is placed at the center of the slab. For the image to be formed on $ S $ itself, which of the following distances between the two mirrors is/are correct:
- JEE Advanced - 2025
- Ray optics and optical instruments
- Let $$ \alpha = \frac{1}{\sin 60^\circ \sin 61^\circ} + \frac{1}{\sin 62^\circ \sin 63^\circ} + \cdots + \frac{1}{\sin 118^\circ \sin 119^\circ}. $$ Then the value of $$ \left( \frac{\csc 1^\circ}{\alpha} \right)^2 $$ is \rule{1cm}{0.15mm}.
- JEE Advanced - 2025
- Some Applications of Trigonometry
JEE Advanced Notification
Concepts Used:
Glucose
Glucose is a simple sugar, also known as dextrose, that is a primary source of energy for living organisms. It is a monosaccharide, meaning it consists of a single sugar unit, and is chemically classified as an aldohexose, which means it has six carbon atoms and an aldehyde functional group.
Glucose is produced by plants through the process of photosynthesis, where it is synthesized from carbon dioxide and water using energy from sunlight. It is also produced in the human body through the breakdown of complex carbohydrates, such as starch and glycogen, in the process of digestion.
Glucose is transported throughout the body via the bloodstream and taken up by cells where it is metabolized to produce energy in the form of ATP. Excess glucose can be stored in the liver and muscles as glycogen for later use.
Read Also: Structure of Glucose and Fructose
Glucose is an important component of many foods, such as fruits, honey, and sweetened beverages. It is also used as a sweetener in the food industry and as a medical treatment for hypoglycemia, a condition characterized by low blood glucose levels.
Measurement of glucose levels in the blood is an important diagnostic tool for monitoring and managing diabetes, a chronic metabolic disorder characterized by high blood glucose levels. Glucose testing can be done using a variety of methods, such as fingerstick testing and continuous glucose monitoring.