Question:

To what radioactive family does $ P{{b}^{207}} $ belongs?

Updated On: Jun 7, 2022
  • $ T{{h}^{232}} $
  • $ N{{p}^{237}} $
  • $ A{{c}^{227}} $
  • $ {{U}^{238}} $
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The Correct Option is C

Solution and Explanation

$ P{{b}^{207}}(207=4\times 51+3) $ belongs to 4n + 3 series or Actinium $ (A{{c}^{227}}) $ series. It starts from $ {{U}^{235}}. $
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