5 × 10-10 vA m
5 × 10-10 m
1.5 × 10-10 m
5 × 10-10 vB m
\(\frac{\mu_A}{\mu_B}\)=\(\frac{\frac{c}{V_A}}{\frac{c}{V_B}}\)=\(\frac{V_B}{V_A}\)=\(\frac{1}{2}\)
Let the thickness be d
\(\frac{d}{v_B}\)−\(\frac{d}{v_A}\)=5×10−10
d=5×10−10×\(\frac{v_Av_B}{v_A-v_B}\)
As vA=2vB
⇒d=5×10−10×2vB
Or
d=5×10−10×vA
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