Question:
Tickets for a concert were sold at Rs. 2, Rs. 4, and Re. 1. Twelve more tickets were sold at Rs. 4 instead of Rs. 2, and twice tickets were sold at Re. 1. If the total amount collected is Rs. 288, then how many tickets of Rs. 2 were sold?
Tickets for a concert were sold at Rs. 2, Rs. 4, and Re. 1. Twelve more tickets were sold at Rs. 4 instead of Rs. 2, and twice tickets were sold at Re. 1. If the total amount collected is Rs. 288, then how many tickets of Rs. 2 were sold?
Show Hint
In problems involving multiple categories and total amounts, assign variables for each category, set up an equation, and solve for the unknowns.
Updated On: Nov 27, 2025
- 30
- 24
- 25
- 28
- 22
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Assign variables.
Let the number of tickets sold at Rs. 2 be \( x \). Then, the number of tickets sold at Rs. 4 will be \( x + 12 \), and the number of tickets sold at Re. 1 will be \( 2x \).
Step 2: Set up the equation based on the total amount collected.
The total amount collected is Rs. 288. The amount collected from each type of ticket is: - From Rs. 2 tickets: \( 2x \) - From Rs. 4 tickets: \( 4(x + 12) \) - From Re. 1 tickets: \( 1(2x) \) Thus, the total amount collected is: \[ 2x + 4(x + 12) + 2x = 288 \] Step 3: Solve the equation.
Simplify the equation: \[ 2x + 4x + 48 + 2x = 288 \] \[ 8x + 48 = 288 \] \[ 8x = 288 - 48 = 240 \] \[ x = \frac{240}{8} = 30 \] Step 4: Conclusion.
Thus, the number of tickets sold at Rs. 2 is 30.
Let the number of tickets sold at Rs. 2 be \( x \). Then, the number of tickets sold at Rs. 4 will be \( x + 12 \), and the number of tickets sold at Re. 1 will be \( 2x \).
Step 2: Set up the equation based on the total amount collected.
The total amount collected is Rs. 288. The amount collected from each type of ticket is: - From Rs. 2 tickets: \( 2x \) - From Rs. 4 tickets: \( 4(x + 12) \) - From Re. 1 tickets: \( 1(2x) \) Thus, the total amount collected is: \[ 2x + 4(x + 12) + 2x = 288 \] Step 3: Solve the equation.
Simplify the equation: \[ 2x + 4x + 48 + 2x = 288 \] \[ 8x + 48 = 288 \] \[ 8x = 288 - 48 = 240 \] \[ x = \frac{240}{8} = 30 \] Step 4: Conclusion.
Thus, the number of tickets sold at Rs. 2 is 30.
Was this answer helpful?
0
0
Top Questions on Number Systems
- What is the remainder when \( 256^{74} \) is divided by 231?
- NMAT - 2025
- Quantitative Aptitude
- Number Systems
- How many numbers \( x \) exist such that \( 10^{11}<x<10^{12} \) and the sum of digits of \( x \) is 1?
- NMAT - 2025
- Quantitative Aptitude
- Number Systems
- How many factors of 1080 contain exactly one trailing zero?
- NMAT - 2025
- Quantitative Aptitude
- Number Systems
- The product of the last 2 digits of $ (1919)^{1919} $ is:
- JEE Main - 2025
- Mathematics
- Number Systems
- The remainder, when \(7^{98}\) is divided by 23, is equal to:
- JEE Main - 2025
- Mathematics
- Number Systems
View More Questions
Questions Asked in NMAT exam
Funky Pizzeria was required to supply Pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which was to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2. Pizzas could be of Thin Crust (T) or Deep Dish (D) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are 4 types of pizzas: T-NC, T-EC, D-NC, D-EC. Partial information about proportions of T and NC pizzas ordered by the three parties are given below.
- There are three groups of students M1, M2, and M3, having 20, 30, and 40 students respectively. If one student each from M1 and M3 leave their respective groups and join M2, the average weight of M1 and M3 decreases by 2 kg each and the average weight of M2 increases by 3 kg. By how much (in kg) does twice the average weight of M2 differ from the sum of the average weights of M1 and M3?
- NMAT - 2025
- Averages
- A and B are employed to complete a work. When A worked at twice his normal efficiency and B worked at half his normal efficiency, the work was completed in 17 days. If A had worked at five times his normal efficiency and B worked at one-fourth of his normal efficiency, the work would have been completed in 10 days. If B works alone, how many days does he need to complete the work?
- NMAT - 2025
- Time and Work
- The questions given below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer:
The number of employees from company A and B is 900 and 1015 respectively. Number of male employees from A is what percent of the number of female employees from A?
Statement I: The number of male employees from B is 10% more than that of the number of male employees from A. The number of female employees from B is 15% more than that of the number of female employees from A.
Statement II: The number of female employees from B is 175 more than that of the number of female employees from A and the difference between the number of male and female employees from B is 135.
- NMAT - 2025
- Data Sufficiency
- Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer:
A, B, and C are three pipes in a tank. A and B are outlet pipes and C is an inlet pipe. The ratio of the efficiency of A : B is 3 : 1 and that of B : C is 1 : 2. What is the capacity of the tank?
Statement I: If all three pipes are opened, the water in the tank will decrease at the rate of 30 litres per minute.
Statement II: The time taken by C to fill the tank is 60 minutes less than the time taken by B to empty the tank.
- NMAT - 2025
- Data Sufficiency
View More Questions