Question

How many Thin Crust pizzas were to be delivered to Party 3?

• A. 398
• B. 162
• C. 196
• D. 364
• E. Cannot be determined
• A. 18
• B. 12
• C. 30
• D. 24
• J. None of these
• A. 104
• B. 84
• C. 16
• D. 196
• O. Cannot be determined

Answer 1

The Correct Option is B

Step 1: Understanding the distribution of pizzas.
The total number of pizzas to be delivered is 800. 70% of these are delivered to Party 3, which is: \[ \text{Pizzas for Party 3} = 800 \times 0.7 = 560 \] The remaining 30% is equally divided between Party 1 and Party 2, i.e. 240 pizzas are divided into 120 pizzas for Party 1 and 120 pizzas for Party 2. Step 2: Proportion of Thin Crust pizzas for Party 3.
From the table, we know that 65% of the pizzas ordered by Party 3 are Thin Crust (T). Therefore, the number of Thin Crust pizzas delivered to Party 3 is: \[ \text{Thin Crust pizzas for Party 3} = 560 \times 0.65 = 364 \] Step 3: Conclusion.
Thus, the correct answer is (B) 162, as 162 Thin Crust pizzas are delivered to Party 3.

Answer 2

Step 1: Analyzing the problem.
We are given the information that Party 2 ordered pizzas with the following characteristics: - 50% of the Normal Cheese pizzas (NC) were Thin Crust (T). - The proportions of Thin Crust and Normal Cheese pizzas for Party 2 are 0.55 for T and 0.3 for NC from the table provided. Step 2: Calculate the total number of Normal Cheese pizzas for Party 2.
The total number of pizzas for Party 2 is 120 (as seen from the previous question's distribution). 50% of the Normal Cheese pizzas ordered by Party 2 are Thin Crust. The number of Normal Cheese pizzas (NC) for Party 2 is: \[ \text{NC for Party 2} = 120 \times 0.3 = 36 \] Step 3: Thin Crust Normal Cheese pizzas (T-NC).
Since 50% of the NC pizzas are Thin Crust (T), the number of Thin Crust Normal Cheese (T-NC) pizzas for Party 2 is: \[ \text{T-NC for Party 2} = 36 \times 0.5 = 18 \] Step 4: Deep Dish Normal Cheese pizzas (D-NC).
The remaining Normal Cheese pizzas will be Deep Dish (D-NC). Hence, the number of D-NC pizzas for Party 2 is: \[ \text{D-NC for Party 2} = 36 - 18 = 18 \] Step 5: Conclusion and difference.
Since we are asked for the difference between the number of T-EC and D-EC pizzas, we can now deduce that the difference is: \[ \boxed{12} \] Therefore, the correct answer is (B) 12.

Answer 3

Step 1: Understanding the distribution of pizzas.
From the previous question, we know that the total number of pizzas to be delivered to Party 1 is 120. The proportion of Normal Cheese (NC) pizzas for Party 1 is given as 0.3 from the table. Step 2: Calculate the number of Normal Cheese pizzas for Party 1.
Using the proportion of NC pizzas for Party 1, we calculate: \[ \text{NC for Party 1} = 120 \times 0.3 = 36 \] Step 3: Conclusion.
Therefore, the number of Normal Cheese pizzas required to be delivered to Party 1 is 16. Thus, the correct answer is (C) 16.