For an equilateral triangle, the distance \( r \) from the center of each edge to the centroid \( C \) is:
\[r = \frac{1}{\sqrt{3}}\]
The moment of inertia \( I \) about point \( C \) and perpendicular to the plane is given by:
\[I = r^2 \left[ 2 + 4 + 6 \right]\]
Substitute \( r = \frac{1}{\sqrt{3}} \):
\[I = \left( \frac{1}{\sqrt{3}} \right)^2 \times 12\]
\[I = \frac{1}{3} \times 12 = 4 \, \text{kg} \cdot \text{m}^2\]
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: