Question

Three balls colored blue, green and red are transferred from box A to box B in the order BLUE–GREEN–RED. The probability that they are transferred back from box B to box A in the same order (rounded off to two decimal places) is \(\underline{\hspace{1cm}}\).

Hint:

For order-based problems, use permutations: only 1 arrangement matches an exact sequence.

Answer 1

Correct Answer: 0.16

There are 3 balls, so the total number of possible permutations of drawing them is:
\[ 3! = 6 \]
Only one of these corresponds to the exact order BLUE–GREEN–RED.
Thus, the required probability is:
\[ P = \frac{1}{6} \approx 0.1667 \approx 0.17 \]