Question

The zero's of a quadratic polynomial \(4y^2+8y \) are

• A. 0, 4
• B. 0, 2
• C. 0, 8
• D. 0, -2

Answer 1

The Correct Option is D

To solve the problem, we need to find the zeros (roots) of the quadratic polynomial:
$ 4y^2 + 8y $

1. Express the Polynomial in Standard Form:
The expression is already in standard form:
$ 4y^2 + 8y = 0 $

2. Factoring the Expression:
Factor out the common term $4y$:
$ 4y(y + 2) = 0 $

3. Applying the Zero Product Property:
Set each factor equal to zero:
$ 4y = 0 \Rightarrow y = 0 $
$ y + 2 = 0 \Rightarrow y = -2 $

Final Answer:
The zeros of the polynomial are $ {0, \, -2} $