1. For isothermal expansion, work done is calculated as:
\(W = -nRT \ln \frac{P_2}{P_1}\)
2. Substituting the given values:
\(W = -(1) \times (2.0) \times (298) \times \ln \left(\frac{10}{20}\right)\)
3. Simplify:
\(W = -596 \times \ln(0.5) = -596 \times (-0.693) \approx -413.14 \text{ calories}\).
0.05 cm thick coating of silver is deposited on a plate of 0.05 m2 area. The number of silver atoms deposited on plate are _____ × 1023. (At mass Ag = 108,d = 7.9 g/cm³)
List I | List II | ||
---|---|---|---|
A | Mesozoic Era | I | Lower invertebrates |
B | Proterozoic Era | II | Fish & Amphibia |
C | Cenozoic Era | III | Birds & Reptiles |
D | Paleozoic Era | IV | Mammals |