1. For isothermal expansion, work done is calculated as:
\(W = -nRT \ln \frac{P_2}{P_1}\)
2. Substituting the given values:
\(W = -(1) \times (2.0) \times (298) \times \ln \left(\frac{10}{20}\right)\)
3. Simplify:
\(W = -596 \times \ln(0.5) = -596 \times (-0.693) \approx -413.14 \text{ calories}\).
